A model rocket is launched from the top of an observation tower
that is 75 feet high. The height
of the rocket, h(t), is
determined by the function
h(t)--16r2 + 48t +75 where t is
the number of seconds elapsed
since the rocket was launched.
When does the rocket land on
the ground? Round to the
nearest hundredth.

>>> t = 3/2 - sqrt(111)/4

>>> t = 3/2 + sqrt(111)/4

Step-by-step explanation:

-16r^2 + 48t +75=0

>>> t = 3/2 - sqrt(111)/4

>>> t = 3/2 + sqrt(111)/4

2? if not the correct answer you might need to provide more information

step-by-step explanation:

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).