Mathematics, 09.04.2021 20:20 azzyla2003

Which could be the function graphed below? On a coordinate plane, a curve starts in quadrant 2 and crosses the y-axis and goes into quadrant 1. The curve opens down and to the right.

f (x) = StartRoot x minus 5 EndRoot + 1
f (x) = StartRoot x minus 2 EndRoot
f (x) = StartRoot x EndRoot

Answers: 1

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Which could be the function graphed below? On a coordinate plane, a curve starts in quadrant 2 and crosses the y-axis and goes into quadrant 1. The curve opens down and to the right. f (x) = StartRoot x minus 5 EndRoot + 1 f (x) = StartRoot x minus 2 EndRoot f (x) = StartRoot x EndRoot

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Another question on Mathematics

Which could be the function graphed below? On a coordinate plane, a curve starts in quadrant 2 and crosses the y-axis and goes into quadrant 1. The curve opens down and to the right.

f (x) = StartRoot x minus 5 EndRoot + 1
f (x) = StartRoot x minus 2 EndRoot
f (x) = StartRoot x EndRoot