What is the solution to the system below? x + 5y = 4 x - 5y = -16

(6,-2)
(2,-6)
(-6,2)
(-2,6)​

(-6,2) third option is correct

Step-by-step explanation:

x+5y=4    equation1

x-5y=-16   equation 2

by adding both equations we got

2x=-12

x=-6

now put x=-6 in any of the equation to get y...

-6+5y=4  equation 1      

5y=4+6

5y=10

y=10/5

y=2

(-6,2)

(-6, 2)

Step-by-step explanation:

Put (-6, 2) into eq1 and eq2

1. (-6) +5(2)= -6 +10 =4  

2.(-6) - 5(2)= -6-10 = -16

only one that works is (-6, 2)

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !