The mass of 4.5 cm3 of iron and 8 cm3 of copper is equal to 101.5g. The mass of 3 cm3 of iron is 6.8g greater than the mass of 2 cm3 of copper. Find the density of iron and the density of copper.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

what are you trying find out?

step-by-step explanation:

if you're trying to figure out how much each ounce cost it would be 0.20

cents each ounce