Determine which polynomial is a perfect square trinomial. Explain your answer. Group of answer choices
A. 49x2 − 28x + 16
B. 9a2 − 30a + 25
C. 25b2 − 45b − 81
D. 16x2 − 24x − 9

The answer is B. 9a2-30a+25

Step-by-step explanation:

First of all, the second sign is going to be +, so you can toss out C and D without checking.

Then you take the square root of the two ends, multiply them, multiply by two and see if it matches.

sqrt(49) * sqrt(16) = 7 * 4 = 28

28 * 2 = 56

56 <> 28

So toss A.

sqrt(9) * sqrt(25) = 3 * 5 = 15

15 * 2 = 30

So the answer is B

(3a - 5)^2 = 9a^2 - 30a + 25

By the way, use ^ to indicate an exponent.

(c, 0) i might be wrong so don't put full faith on my answer

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3