Find four consecutive terms in an A. P whose sum is 12 & sum of 3rd & 4rt term is 14.(Assume the four consecutive terms in A. P. are a-d ,a, a+d, a+2d.)​

whose sum is 12 and the sum of 3rd and 4th term is 14. ∴ The four consecutive terms of A.P. are – 3, 1, 5 and 9.

it's so easy

i dont know sorry

step-by-step explanation:

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!