In ΔRST, r = 620 inches, s = 840 inches and t=230 inches. Find the area of ΔRST to the nearest square inch.

24179 square inches

Step-by-step explanation:

In ΔRST, r = 620 inches, s = 840 inches and t=230 inches. Find the area of ΔRST to the nearest square inch.

We use the formula

Heron's formula = √s(s - a)(s - b)(s - c)

Where s = a + b + c/2

Solving for s

s = 620 + 840 + 230/2

s = 845

Solving for the area of the triangle

= √845 × (845 - 620) × (845 - 840) × (845 - 230)

= √584634375

= 24,179.213696893 square inches

Approximately = 24179 square inches

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

part 1 answer = 8

part 2 answer = 72

step-by-step explanation:

part 1 explanation = add all of the numbers, then divide by how many numbers you have. so, 200/25 = 8.

part 2 explanation = not gonna lie, this is hard to explain, so just google how to do it.