Solve the right triangle. Round decimal answers to the nearest tenth. B
14
6
A
b
С

A^2 + B^2 = C^2

6^2 + 14^2=c^2

36+196=C^2

232=c^2

square root of 232= c

therefore c is equal to 15,23

Step-by-step explanation:

use the Thereom of Pythagoras

it's both, now can you answer my most recent question?

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐