Here are the tips of 25 randomly selected patrons, measured in percent of total bill. 20.8 18.7 19.9 20.6 21.9 23.4 22.8 24.9 22.2 20.3 24.9 22.3 27.0 20.4 22.2 24.0 21.1 22.1 22.0 22.7 19.1 20.6 22.3 22.0 29.4 The standard deviation of tips is known to be 2.5. a) What is the 94% confidence interval for the mean tip of patrons if the distribution of tips is approximately Normal? b) What is the 98% confidence interval for the mean tip of patrons if the distribution of tips is unknown?

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

the inequality is:

250c+180g≥950

step-by-step explanation:

let c denotes the number of days in a week   miyoko worked as a cryptographer.

and g denotes the number of days in a week she works as a geologist.

now we are given that she earns $250 for every day she works as a cryptographer,and earns $180 for every day she works as a geologist.

now miyoko's goal is to earn more than $950 this week.

hence, the inequality could be represented as:

250c+180g≥950

the answer is simply just 6n add the two together as they have an n

12 cups   is the answer

step-by-step explanation: