Use the identity (x+y)(x−y)=x^2−y^2 to find the difference of two numbers if the sum of the numbers is 12 and the difference of the squares of the numbers is 48. Thank you!!

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

1. perpendicular

2. parallel

3. perpendicular