Find the perimeter of these figures *
please*

The perimeter of figure a is 44 inches, the perimeter of figure b is 72 inches.

Step-by-step explanation:

The sides of figure a is 8; 2; 3; 12; 2; 12; 3; 2, to get the perimeter, add all the sides together, which will be 8 + 2 * 2 + 3 * 2 + 12 * 2 = 8 + 4 + 6 + 24 = 12 + 30 = 42 inches. The sides of figure b is 3; 3; 3; 3; 13; 13; 5; 5; 5; 5; 7; 7, to get the perimeter, add all the sides together, which will be 3 * 4 + 13 * 2 + 5 * 4 + 7 * 2 = 12 + 26 + 20 + 14 = 32 + 40 = 72 inches.

a) 44

2 + 8 + 2 + 8 + 12 + 12 = 44

b) 72

13 + 13 + 3 +3 +3 +3 +5 +5 +5 +5 +7 +7 = 72

Step-by-step explanation:

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

there are no answer choices

step-by-step explanation: