Somebody please help me on :( and the links y’all keeping sending are not working so please just help me on A regular 16-gon has a radius of 10 meters

Part A: determine the length of the apothem

Part B: determine the perimeter of the polygon

  9 in

Step-by-step explanation:

For an n-sided polygon, the length of the apothem is ...

 a = r·cos(180°/n)

We assume your problem statement is saying the radius is 10 inches. For a hexagon, n=6 and we have ...

 a = (10 in)cos(30°) ≈ 8.66 in

Rounded to the nearest inch, the apothem is 9 in.

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

deez nu tz

step-by-step explanation: