Given two right triangles, KLM and RST, m∠L = m∠S = 90°. Which statement is not necessarily true? Options
If m∠K = m∠R, ΔKLM ~ ΔRST
If KLRS = LMST, ΔKLM ~ ΔRST
If m∠M = m∠T, ΔKLM ~ ΔRST
If KLRT = LMST, ΔKLM ~ ΔRST

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.

      2

  2 is to go somewhat to the top right of a because it is squared    

v= a h/3