A system of equations is shown. y = 3x - 2

y = x2

What are the solutions to the system of equations?​

x = 1, y = 1

x = 2, y = 4

Step-by-step explanation:

substitution method:

x² = 3x - 2

x² - 3x + 2 = 0

(x - 2)(x - 1) = 0

x = 2

x = 1

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer