there are 6 boys and 5 girls in the debate class. kids are being selected to go present their work without getting opt-out where is the probability that a boy will be selected to present twice?

30%?

Step-by-step explanation:

6 boys, 5 girls

first selection is a 6/11 chance it's a boy.

second seletion is a 6/11 chance it's a boy.

6/11 times 6/11 is... 0.2975 or about a 30% chance ( i think)

Just multiply the probability of the first event by the second. For example, if the probability of event A is 2/9 and the probability of event B is 3/9 then the probability of both events happening at the same time is (2/9)*(3/9) = 6/81 = 2/27.

idk

step-by-step explanation: