Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a radius of 7 feet and a height of 7 feet. Container B has a radius of 4 feet and a height of 19 feet. Container A is full of water and the water is pumped into Container B until Conainter B is completely full. To the nearest tenth, what is the percent of Container A that is full after the pumping is complete?

The percentage ≅ 48.4%

Step-by-step explanation:

* Lets revise how to find the volume of a container shaped cylinder

- The volume of any container = area of its base × its height

- The base of the cylinder is a circle, area circle = 2 π r,

 where r is the length of its radius

* In container A:

∵ r = 13 feet  , height = 13 feet

∴ Its volume = π (13)² × (13) = 2197π feet³

* In container B:

∵ r = 9 feet  , height = 14 feet

∴ Its volume = π (9)² × (14) = 1134π feet³

* So to fill container B from container A, you will take from

 container A a volume of 1134π feet³

- The volume of water left in container A = 2197π - 1134π = 1063π feet³

* To find the percentage of the water that is full after pumping

 is complete, divide the volume of water left in container A

 by the original volume of the container multiplied by 100

∴ The percentage = (1063π/2197π) × 100 = 48.3841 ≅ 48.4%

y = - 6

step-by-step explanation:

given the point (- 2, y) lies on the graph then it is a solution of it's equation.

substitute x = - 2 into the equation for value of y

y = 3(- 2) = 3 × - 2 = - 6

the point on the graph is (- 2, 6)