I need this before 3

The little circle is black.

The first top row is: purple(7), blue(8), purple(7), blue(8), purple(7), blue(8).

The 2nd row is: pink(5), orange(6), yellow(4), green(2), red(1), brown(10)

The 3rd row is: brown(10), red(1), green(2), yellow(4), orange(6), pink(5)

The top handle color is: brown(10)

The bottom handle color is: black(3)

Step-by-step explanation:

I worked it out

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.