During a flu epidemic, 35% of the school's students have the flu. Of those with the flu, 90% have high temperatures. However, high temperatures are possible for people who do not have the flu. It is estimated that
12% of those without the flu have high temperatures.
If a student has a high temperature, what is the probability that the student has the flu?

0.8015 = 80.15% probability that the student has the flu

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

In which

P(B|A) is the probability of event B happening, given that A happened.

is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Has high temperature.

Event B: Has the flu

Probability of a student having high temperatures:

90% of 35%(have the flu)

12% of 100 - 35 = 65%(do not have the flu). So

Probability of having high temperatures and the fly?

90% of 35%, so

If a student has a high temperature, what is the probability that the student has the flu?

0.8015 = 80.15% probability that the student has the flu

b. x- 48 =120

step-by-step explanation:

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a