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Mathematics, 14.04.2021 15:50 dianasr424

Which shows how to use similar right triangles to find the equation of the line through (0,6) and any point, (x, y), on the line?
y-0
m
0
So y = ma.
(x, y)
(1. m+b)
y - b
2-0
m+b-b
1-0
so y = mx + b.
(0,b)
(0,0)
2-0
y-b
m+bb
1 - 0
SO X = my + mb.
y-1
m
= i, so y — b = mx +b.
Done

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