Acircle has its center at the center of a square with 3-inch sides. find the area of the square not covered by the circle round the answer to the nearest tenth.
a) 21.4 in²
b) 1.9 in²
c) 0.8 in²
d) 7.2 in²

So in order for us to know the area of the square that is not covered by the circle, we need to find first both the areas of the square and the circle.
So for the area of the square it is A = sxs. And for the circle is A = pi*r^2.
Let us find the area of the square first given that the side is 3 inches.
So A = 3*3
    A = 9 square inches.
Next is the area of the circle. Since the center of the circle is the same with the center of the square, the radius would be 1.5.
SO, A = (3.14)(1.5)^2
       A = 2.25 (3.14)
        A = 7.065 square inches.
Next, we deduct the area of circle from area of square and the result would be 1.935 in². So the answer for this would be option B.
Hope this answer helps.

Horizontal change or the change of x

For range i think it’s area