Can someone please help me with this math problem? Please. Simplify the expression:(2x-3y)^2/(3y-2x)^2 Ava simplified the expression and said that the value is -1. (2x-3y)^2/(3y-2x)^2 (2x-3y)^2/-(2x-3y)^2 and then she has both of them crossed out (2x-3y)^2/-1(2x=3y)^2 =-1 Is Ava's solution correct? If not, find and explain her mistake. Give the correct solution.

Ava is incorrect

Step-by-step explanation:

Given

Required

Determine if Ava is correct or not

Ava's solution is incorrect and the proof is as follows;

Apply the following law of indices;

Rewrite the numerator

Cross out the common factor of the numerator and denominator

Hence, the solution is 1; not -1

Her mistake is that, she did not apply the square on -1, after she factorize the denominator

the answer is somewhere there guys it really . there im just not gonna answer

step-by-step explanation:

but i'm guessing ur first option tho

b) 1/3 * 1/5

step-by-step explanation:

each smallest part is 1/15 since the written one is 1/5 and it's divided by 3 equal parts. (1/5 )/3 = 1/15 = 1/3 * 1/5