to solve the problem tan^-1(cos(pi/2)) find the angle in the interval [-pi/2, pi,2] whose tangent equals 0.

The cosine of pi/2 is 0 so the problem really says "find the angle between - pi/2 and pi/2 whose tan = 0. That would be the same as asking for the angle whose sin is 0. That would be 0.

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How many shares did he have to begin with?