8-10 deal with the ambiguous ssa case. for each find all possible solutions and sketch the triangle in each case.
8. a=50 degrees, a=15, b=12
9. a=50 degreees, a=10, b=15
10. a=47 degrees, a=1.5 b=2

For problem 8:

sin A/a sinB/b = sinC/c 

so sin50/15 = sinB/12 

0.766/15 =sinB/12 

0.051066 = sin B/12 

sin B = 0.6128 
B = 37.79 degrees 

sum of angles must equal 180 deg therefore C = 180-50-37.79 = 92.21 degrees and .766/15 = sin92.21/c 

.051066= 0.99925/c 
c = .99925/0.051066 = 19.567 

Problems 9 and 10 can also be done with the same method as problem 8.

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A= b/2 because u simplying both sides of equation