Help and explain how you got it.

no trolling or report!

I am 100% confident in my calculations. I'm not 100% sure about interpreting. Sorry I can't be of more help.

Part A:

Median: 4.5

IQR: 3.5

Mode: 6

I think the median/IQR is a better measure of center and variability because the range of data is so big (10 - 0 = 10), and the data skews to the right with the 6s.

Part B:

I would say no. It is the one that occurs most frequently, but there are many more times she rides less than 6, which is why the median is 4.5

Step-by-step explanation:

Mean: 4.714

MAD: 2.43

Median: 4.5

IQR: 3.5

Mode: 6

the number set in order:

0, 2, 2, 2.5, 2.5, 3, 4, 5, 6, 6, 6, 8, 9, 10

The median (middle number) is two numbers: 4 and 5, so the median is 4.5

The first quartile/Q1 (middle of the bottom half of data) is 2.5, the third quartile/Q3 (middle of the top half of data) is 6. So the IQR (interquartile range) is 6 - 2.5 = 3.5

The mean is the sum of the numbers divided by the quantity of the numbers, so 66/14 = 4.714

the mean absolute deviation is found by calculating the mean, and then finding the absolute value of the difference between each number of the set and the mean...then adding those together and finding the mean of that set. Labor intensive, but that's 34/14 = 2.42857143

answer: expected value of x = 1.0

step-by-step explanation:

p(x=0) = 0.25

p(x=1) = 0.50

p(x=2) = 0.25

expected value for x = 0×0.25 + 1×0.5 + 2×0.25 = 1.0