The ratio of the numerator to the denominator of a fraction is 2 to 3. if both the numerator and the denominator are increased by 2, the fraction becomes 3/4. what is the original fraction?
which of the following systems of equations can be used to solve the problem?
n + 4 = 3 and d + 5 = 4
3n - 2d = 0 and 4n + 2 = 3d + 2
3n = 2d and 4n + 8 = 3d + 6

3n = 2d and 4n + 8 = 3d + 6

Step-by-step explanation:

The ratio of the numerator to the denominator of a fraction is 2 to 3. If both the numerator and the denominator are increased by 2, the fraction becomes 3/4.  

Let n be the numerator and d be the denominator

The ratio of the numerator to the denominator of a fraction is 2 to 3

Corss multiply it , the equation becomes

3n = 2d

If both the numerator and the denominator are increased by 2, the fraction becomes 3/4.  

add 2 with n  and d

Cross multiply it

4(n+2) = 3(d+2)

4n+8 = 3d+6

answer: plz give a pic and answer choices so i can answer!

step-by-step explanation:

your answer would be 12