A spinner is divided into equal sections, each labeled with a number between one and five. Over the course of 150 spins, what is the best estimate of how many times you would expect that the hand of the spinner will stop on a 3?

∞ this is your sign

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92

2, 2, 2 or -4, 20, 29

step-by-step explanation:

there is two ways you can do it.