Find the 6th term of the arithmetic sequence with
a9 = 64 and a12 = 88; a6 =

In order to solve for a nth term in an arithmetic sequence, we use the formula written as:

an = a1 + (n-1)d

where an is the nth term, a1 is the first value in the sequence, n is the term position and d is the common difference.

First, we need to calculate for d from the given values above.  
a9 = 64 and a12 = 88

an = a1 + (n-1)d
64= a1 + (9-1)d

an = a1 + (n-1)d
88= a1 + (12-1)d

a1 = 0
d = 8
 
The 6th term is calculated as follows:

a6 = 0 + (n-1)d
a6= (6-1)(8)
a6 = 40