Which represents the sum of the geometric series: 6 + 12 + 24 + 48 + … + 12,288?
12,372

13,818

18,426

24,570

First, we need to solve for the common ratio from the data given by using the equation.

a(n) = a(1) r^(n-1)
12 = 6 r^(2-1)
r = 2

12288 = (6) 8^(n-1)

2048 = 8^(n-1)

 n = 11

Then, we can find the sum by:

Sum of terms inside the brackets is 4095, i.e. 2^12 - 1. 
So the required sum = 6 x 4095 
= 24,570

16

step-by-step explanation:

2 x 40 = 80

80/5

= 16