In a class of 10, there are 5 students who play soccer. If the teacher chooses 2 students, what is the probability that both of them play soccer?

Step-by-step explanation: 5/10=1/2  - if one student  are chosen, who plays soccer

4/9 if then the second student are chosen, who plays soccer

1/2*4/9=2/9 the probability that both  students play soccer

option 1 is correct.

step-by-step explanation:

y varies inversely with x and constant of variation is 4

the equation will be:

y = k/x

where k =4 so,

y = 4/x

if we put values of x of option 1 in the above equation and find values of y

y = 4/-2 => y =-2

y = 4/-1 => y = -4

y = 4/1 => y = 4

y = 4/2 => y =2

so, all the values of x and y are correct.

if we put values of x given in other options and find value of y we cannot find whole table satisfying the equation.

hence option 1 is correct.

  n=   0.0000 - 0.3750 i  

  n=   0.0000 + 0.3750 i

step-by-step explanation:

one of these should be correct