The math club is sponsoring a bake sale. if their goal is to raise at least $200, how many pies must they sell at $4.00 each in order to meet that goal? write, solve, and graph an inequality that represents this situation.

a 4.00p< _200; p< _50
< > closed going to left from positive 50
-125 -100 -75 -50 -25 0 25 50 75 100 125

b. 4.00p< _200; p< _50
< > open going to left from positive 50
-125 -100 -75 -50 -25 0 25 50 75 10 125

c 4.00p> _200; p> _50
< > open going to right from positive 50
-125 -100 -75 -50 -25 0 25 50 75 100 125

d 4.00p> _200; p> _50
< > closed going to the right from positive 50
-125 -100 -75 -50 -25 0 25 50 75 100 125

D.  

Step-by-step explanation:

We have been given that The Math Club's goal sells each pie for $4.00, so the money raised from 'p' pies would be 4.00p.

We are also told that their goal is to raise at least $200. This means that money raised from 'p' pies should be greater than or equal to 200. We can represent this information in an inequality as:

Now, we will solve for 'p' by dividing both sides of our inequality by 4.00.

Upon graphing our inequality we will get our desired graph as shown in the attached file.

Since 'p' is greater than or equal to 50, so our line will have a solid dot on 50 and it will go in positive direction that is right. Therefore, option D is the correct choice.

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

okay wait before i answer, is this for your points on a graph?