A ladder leans against a building, making a 70° angle of elevation with the ground. The top of the ladder reaches a point on the building that is 39 feet above the ground. To the nearest tenth of a foot, what is the distance between the base of the building and the base of the ladder?

Question 4 options:

13.3 ft

14.2 ft

36.6 ft

41.5 ft

14.2feet

Step-by-step explanation:

Given the following

Angle of elevation = 70degrees

Height of the building from the ground = 39feet (opposite)

Required

distance between the base of the building and the base of the ladder (adjacent)

Using the SOH CAH TOA identity

Tan theta = opp/adj

Tan 70 = 39/d

d = 39/tan 70

d = 39/2.7475

d =  14.2

Hence the distance between the base of the building and the base of the ladder is 14.2feet

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet