Find the values of x for which the following inequalities are satisfied 2x^2+3x<14

x<-3.5 or x<2

Step-by-step explanation:

2x²+3x<14

2x²+3x-14<0

2x²-4x+7x-14<0

2x(x-2)+7(x-2)<0

(2x+7)(x-2)<0

2x+7<0 or x-2<0

2x<-7 or x<2

x<-3.5

32/80  

91/140

the last one 54 doesn't go into 45. 54/100 ?

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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