Jaquelyn wants to start getting to school on time more often. She is looking at some of her habits. On Monday, she is late twenty percent of the time.
When she is late on Monday, she is late on Tuesday 60% of the time.
When she is not late on Monday, she is late on Tuesday 20% of the time.
What is the approximate probability that Jaquelyn will be late on Tuesday, given she was late to school on Monday?

45%?

Step-by-step explanation:

im not sure

y=mx+

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)