In a popular online role playing game, players can create detailed designs for their character's "costumes," or appearance. Olivia sets up a website where players can buy and sell these costumes online. Information about the number of people who visited the website and the number of costumes purchased in a single day is listed below. 144 visitors purchased no costume. 182 visitors purchased exactly one costume. 9 visitors purchased more than one costume. Based on these results, express the probability that the next person will purchase no more than one costume as a decimal to the nearest hundredth.

There is a 54.328% probability that the next person will purchase no more than one costume.

Step-by-step explanation:

Since in a popular online role playing game, players can create detailed designs for their character's "costumes," or appearance, and Olivia sets up a website where players can buy and sell these costumes online, and information about the number of people who visited. the website and the number of costumes purchased in a single day states that 144 visitors purchased no costume, 182 visitors purchased exactly one costume, and 9 visitors purchased more than one costume, to determine, based on these results, the probability that the next person will purchase no more than one costume as a decimal to the nearest hundredth, the following calculation must be performed:

144 + 182 + 9 = 335

335 = 100

182 = X

182 x 100/335 = X

18,200 / 335 = X

54,328 = X

Therefore, there is a 54.328% probability that the next person will purchase no more than one costume.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.