a theater has 49 seats in the first row, 52 seats in the second row, 55 seats in the third row, and so on. how many seats are there in row 20

106

Step-by-step explanation:

this question represents an arithmetic sequence problem where you can use this formula: a(n) = a(1) + d(n-1)  where 'n' is value you're solving for, a(1) is the initial value, and 'd' is the common difference

a(20) = 49 + 3(20-1)

= 49 + 3(19)

= 49 + 57

= 106

24

step-by-step explanation:

the graph shows 30% of students walk. 80 students were questioned, so the number that said they walk is

30% × 80 = 0.30 × 80 = 24

id

step-by-step explanation:

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