One antifreeze solution is 26% alcohol and another is 11% alcohol how much of each mixture should be added to make 24 l of a solution tgat is 21% alcohol?

Step-by-step explanation:

One antifreeze solution is 26% alcohol and another is 11% alcohol how much of each mixture should be added to make 24 l of a solution that is 21% alcohol?

Let us represent

First solution =>x

Second solution => y

System of equations

x + y = 24Equation 1

x = 24 - y

26% × x + 11% × y = 21% × 24

= 0.26x + 0.11y = 5.04... Equation 2

i have no clue at all sorry

step-by-step explanation:

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2