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Mathematics, 17.04.2021 06:20 310000982
Given: Quadrilateral ABCD has vertices A(-5,6), B(6,6), C(8,-3), and D(-3,-3).
Which of the following ways can prove that quadrilateral ABCD is a parallelogram but is neither
a rhombus nor a rectangle?
A:The diagonals are congruent and perpendicular.
B:The midpoints of the diagonals are the same, the diagonals are not congruent, and
two adjacent sides are not congruent.
C
The four sides are congruent and the diagonals are perpendicular.
D
The slopes of the adjacent sides are negative reciprocals of one another and the
midpoints of the diagonals are the same.
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Given: Quadrilateral ABCD has vertices A(-5,6), B(6,6), C(8,-3), and D(-3,-3).
Which of the followi...
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