The width of a box is two-third of its length and height is one-third of its length. If the volume of the box is 1296 m3,
ind the area of base of the box.​

216m² is your answer

Step-by-step explanation:

given

width [b]=2/3 ×l

length [l]=l

height [h]=1/3 l

we have

volume of cuboid =l×b×h

1296m³=l×2/3×l×1/3×l

1296m³=2/9×l³

l³=1296×9/2=5832

l³=18³

length [l]=18m

breadth [b]=2/3×18=12m

area of base of box =l×b=18×12=216m²

d i think

step-by-step explanation:

b) k’(6, 4); l’(3, 3)

step-by-step explanation:

a 270° clockwise rotation maps every point (x, y) to (y, -x). (it negates the x-coordinate and then switches it and the y-coordinate.)

this means the endpoints of the side congruent to kl, k' and l', would be mapped as:

k'(-4, 6)→(6, 4)

l'(-3, 3)→(3, 3)