2x=8(x^2)
What is the solution of this maths equation?

x=0,x=1/4

Step-by-step explanation:

2x=8(x^2)

Subtract 8(x^2) from both sides

2x-8x^2=8x^2-8x^2

Simplify

2x-8x^2=0

Factor 2x-8x^2;

2x-8x^2

=-8xx+2x

Rewrite 8 as 2*4

=-2*4xx+2x

Factor out common term -2x

=-2x(4x-1)

-2x(4x-1)=0

x=0 or 4x-1=0

Solve 4x-1=0;x=1/4

4x-1=0

Add 1 to both sides

4x-1+1=0+1

Simplify

4x=1

Divide both sides by 4

4x/4=1/4

Simplify

x=1/4

The solutions to the quadratic equation are;

x=0,x=1/4

Hope this helped

4

step-by-step explanation:

assuming you mean addition: addition and subtraction are reverse operations.

step-by-step explanation: