Which is the equation of the line that has a slope of -3 and includes the point (2, 4)?

y= -3x + 10

Step-by-step explanation:

we can answer this question thanks to this formula:

y-y1 = m(x-x1) where y1 and x1 indicate the coordinates of the given point and m indicates the slope

y-4 = -3(x-2)

y = -3x+6+4

y= -3x + 10

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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