Events A and B are mutually exclusive with P(A) equal to 0.264 and P(A or B) equal to 0.602. Find the following probabilities. Part 1 of 3
P(B)
0.338
Part: 1/3
Part 2 of 3
P(not A) =

wedfghjkl;

tyuiop[]ghjkl;

step-by-step explanatio89

3/6 chance

step-by-step explanation:

half of the nubers are odd numbers (1,3,5) which in that case if you would be told to simplify it would be 1/2

1^3 + 2^3 + 3^3 +4^3 = (1+2+3+4)^2

step-by-step explanation:

i am only able to answer the first part. i am not sure about the second part. sorry

b. f(x) = –√x + 3this is the correct answer