Find the nth term of this quadratic sequence 4 9 16 25 36

Step-by-step explanation:

a₁ = 4 = 2² = (1 + 1)²

a₂ = 9 = 3² = (2 + 1)²

a₃ = 16 = 4² = (3 + 1)²

a₄ = 25 = 5² = (4 + 1)²

a₅ = 36 = 6² = (5 + 1)²

Therefore:

               aₙ = (n + 1)² = n² + 2n + 1

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

so then what are you asking?

step-by-step explanation: