How many mg of a metal containing 62 percent nickel must be combined with 4 mg of pure nickel to form an alloy containing 78 percent nickel? Which of the following equations could be used to solve this?

3.29 milligrams of a metal containing 62 percent nickel must be combined with 4 mg of pure nickel to form an alloy containing 78 percent nickel.

Step-by-step explanation:

To determine how many mg of a metal containing 62 percent nickel must be combined with 4 mg of pure nickel to form an alloy containing 78 percent nickel, the following calculations must be performed:

50 + 0.62X = 78

0.62X = 78 - 50

0.62X = 28

X = 28 / 0.62

X = 45.16

100 - 45.16 = 54.84

54.84 = 4

45.16 = X

45.16 x 4 / 54.84 = X

180.64 / 54.84 = X

3.29 = X

Therefore, 3.29 milligrams of a metal containing 62 percent nickel must be combined with 4 mg of pure nickel to form an alloy containing 78 percent nickel.

I go to your school

Step-by-step explanation:

4

step-by-step explanation:

6 (donuts) divided by 3 is 2.

so 2/3 means 2 times 2, which is 4/6.

you get two and your friend gets four.

step-by-step explanation:

circumference divided by 3.141592654 then timesthe radius twice