What is the area of KDL to the nearest tenth of a square inch? Use special right triangles to help find the height. Show your work

8

Step-by-step explanation:

This is a 45-45 traingle which mean that the two sides that aren't the hyptonouse are equal (because their angles are equal)

We will let x equal the length of one of the sides

we have

x²+x²=(4√2)²

2x²=32

x²=16

x=4

this means that the length of the two missing sides are 4

Now using the area of a traingle formula we can solve for the area

A=.5*b*h

.5*4*4=8

.5*4*4

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet