Solve this please .​

The sum of reciprocals is 2/3.

You don't need complex numbers to solve this, but if you try to find a and b you will need complex numbers.

Step-by-step explanation:

a+b = 2

a*b = 3

1/a + 1/b = x

(a*b)*(1/a + 1/b) = (a*b)x

b + a = (a*b)(x)

2 = 3x

x = 2/3

b = 2 - a

a*(2 - a) = 3

-a^2 + 2a = 3

-a^2 + 2a - 3 = 0

a^2 - 2a + 3 = 0

let's solve the quadratic equation

a^2 - 2a + 3 = a^2 - 2a + 1 + 2 = (a - 1)^2 + 2 = 0

(a - 1)^2 = -2

these options correspond to a and b from the original question.

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

x-3y=4

step-by-step e