Aradioactive material has a half-life of 18.4 days. after 55.2 days, there were 177 mg of the material. what mass of the material was originally present?

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.

$75.00

step-by-step explanation:

i = prt

i = 1,5000 * 0.025 * 2

i = 75