Country Financial, a financial services company, uses surveys of adults age and older to determine if personal financial fitness is changing over time (USA Today, April 4, 2012). In February of 2012, a sample of adults showed indicating that their financial security was more than fair. In February of 2010, a sample of adults showed indicating that their financial security was more than fair. a. State the hypotheses that can be used to test for a significant difference between the population proportions for the two years. - Select your answer - - Select your answer - b. What is the sample proportion indicating that their financial security was more than fair in 2012

Complete question :

Country Financial, a financial services company, uses surveys of adults age 18 and older to determine if personal financial fitness is changing over time (USA Today, April 4, 2012). In February of 2012, a sample of 1000 adults showed 410 indicating that their financial security was more than fair. In February of 2010, a sample of 900 adults showed 315 indicating that their financial security was more than fair. a. State the hypotheses that can be used to test for a significant difference between the population proportions for the two years. H : Pi - P2 - Select your answer HA : P1 P2 - Select your answer - b. What is the sample proportion indicating that their financial security was more than fair in 2012? Round your answer to two decimal places. In 2010?

H0 : p1 - p2 = 0

H1 : p1 - p2 ≠ 0

Phat 2010 = 0.35

Phat 2012 = 0.41

Step-by-step explanation:

The null and alternative hypothesis :

H0 : p1 - p2 = 0

H1 : p1 - p2 ≠ 0

The null means there is no difference in proportion for the two years while the alternative claims that there is difference in proportion for the two years.

Sample proportion for 2010:

Phat = x / n

x = 315 ; n = 900

Phat = 315 / 900

Phat = 0.35

Sample proportion for 2012 :

Phat = x / n

x = 410 ; n = 1000

Phat = 410 / 1000

Phat = 0.41

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

answer: hey there,

the answer you are looking for is a..

hope this you!