Nolan has some nickels and some dimes he has no more than 19 coins worth no less than $1.30 combined if Nolan has 5 nickels determine all possible values for the number of dimes that he could have

10.5 ≤ y ≤ 14

Step-by-step explanation:

A nickel is worth 5 pennies. Changing over to dollars, it becomes  

5/100 = $0.05  

A dime is worth dime. Changing over to dollars, it becomes  

10/100 = $0.1  

Allow x to address the number if nickels.  

Allow y to address the quantity of dimes.  

He has close to 19 coins. This implies that  

x + y ≤ 19  

He has no under $1.30 joined. This implies that  

0.05x + 0.1y ≥ 1.3  

On the off chance that Nolan has 5 nickels, subbing x = 5 into x + y ≤ 19, it becomes  

5 + y ≤ 19  

y ≤ 19 - 5  

y ≤ 14  

subbing x = 5 into 0.05x + 0.1y ≥ 1.3, it becomes  

0.05 × 5 + 0.1y ≥ 1.3  

0.25 + 0.1y ≥ 1.3  

0.1y ≥ 1.3 - 0.25  

0.1y ≥ 1.05  

y ≥ 1.05/0.1  

y ≥ 10.5  

Along these lines, all potential qualities for the quantity of dimes that he could have would be  

10.5 ≤ y ≤ 14