David found and factored out the GCF of the polynomial 80b4 – 32b2c3 + 48b4c. His work is below. GFC of 80, 32, and 48: 16
GCF of b4, b2, and b4: b2
GCF of c3 and c: c
GCF of the polynomial: 16b2c
Rewrite as a product of the GCF:
16b2c(5b2) – 16b2c(2c2) + 16b2c(3b2)
Factor out GCF: 16b2c(5b2 – 2c2 + 3b2)
Which statements are true about David’s work? Check all that apply.

The GCF of the coefficients is correct.
The GCF of the variable b should be b4 instead of b2.
The variable c is not common to all terms, so a power of c should not have been factored out.
The expression in step 5 is equivalent to the given polynomial.
In step 6, David applied the distributive property.

8 apples are left.

step-by-step explanation:

10-2=8

10 apples

take 2

now u have 8

definition: a circle is the  set of all points in a plane that are equidistant  from a given  point  called the center of the circle. we use the symbol ⊙ to represent a circle. the a line segment from the center of the circle to  any point  on the circle is a radius of the circle.

step-by-step explanation:

i googled it and this is what i got i don't know how it is. sorry.

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.  

probability for j is 1/4

while

a is 1/6