RYUCU Question 6
5 points
6. The average number of hours of sleep of Ms. Gambino's and Mr. Joe's
classes is shown below. Which of the following statements is best
supported by the data?
MS CAMINOS CLASS
WE JOCS CLASS
OUR
HOURS
F. The median number of hours slept in Ms. Gambino's class is less than the median
number of hours in Mr. Joe's class
G. The data for Ms Gambino's class is symmetrical, while the data for Mr Joe's class
is skewed right
H The range of data in Mt. Joe's class is less than the range of data is Ms Gambino's
class
J. The mode of the data in Ms. Gambino's class was equal to the mode of the data in
Mr Joe's class
Page 7 of 9
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i would pic false cause it goes down towards negative

step-by-step explanation:

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺

oof

step-by-step explanation: